Step-by-step explanation:
mean = sum of all data points / number of data points
(22+16+18+14+16+34+20)/7 = 140/7 = 20
median is the number, where half of the data points are smaller, and the other half are larger.
first we need to sort the data points
14, 16, 16, 18, 20, 22, 34
median = 18
mode is the data point occurring most often.
mode = 16 (occurring 2 times, while the others occur only once).
range is the difference between the largest and the smallest data point.
range = 34 - 14 = 20
Answer:
Step-by-step explanation:
Answer:
3/1
Step-by-step explanation:
The average rate of change is the distance between y values divided by the distance between x values. We know this as rise/run or slope for linear equations. For non-linear equations, we calculate the average over an interval.
This function has y-values of -1 at x=0 and 5 at x=2.
We add -1+5=6 and divide this by 2-0=2.
6/2=3.
The y-values on average change 3 units for every 1 unit of the x-values.
Answer:
After Two Hours.
Step-by-step explanation:
A simple way to do it is to:
1. Add 50+55, it is equal to 105. This is after one hour, so we know that it's more than this.
2. Add 50+55 to 105, This is after two hours, and we get 210, so we know that it has to be equal to 2 hours.
Answer:
Option A is correct.
Solution for the given equation is, ![x = 0^{\circ}](https://tex.z-dn.net/?f=x%20%3D%200%5E%7B%5Ccirc%7D)
Step-by-step explanation:
Given that : ![2\cos^2x -\cos x -1 =0](https://tex.z-dn.net/?f=2%5Ccos%5E2x%20-%5Ccos%20x%20-1%20%3D0)
Let ![\cos x =y](https://tex.z-dn.net/?f=%5Ccos%20x%20%3Dy)
then our equation become;
.....[1]
A quadratic equation is of the form:
.....[2] where a, b and c are coefficient and the solution is given by;
![x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Comparing equation [1] and [2] we get;
a = 2 b = -1 and c =-1
then;
![y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B-%28-1%29%5Cpm%20%5Csqrt%7B%28-1%29%5E2-4%282%29%28-1%29%7D%7D%7B2%282%29%7D)
Simplify:
![y = \frac{ 1 \pm \sqrt{1+8}}{4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B%201%20%5Cpm%20%5Csqrt%7B1%2B8%7D%7D%7B4%7D)
or
![y = \frac{ 1 \pm \sqrt{9}}{4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B%201%20%5Cpm%20%5Csqrt%7B9%7D%7D%7B4%7D)
![y = \frac{ 1 \pm 3}{4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B%201%20%5Cpm%203%7D%7B4%7D)
or
and ![y = \frac{1 -3}{4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%20-3%7D%7B4%7D)
Simplify:
y = 1 and
Substitute y = cos x we have;
![\cos x = 1](https://tex.z-dn.net/?f=%5Ccos%20x%20%3D%201)
⇒![x = 0^{\circ}](https://tex.z-dn.net/?f=x%20%3D%200%5E%7B%5Ccirc%7D)
and
![\cos x = -\frac{1}{2}](https://tex.z-dn.net/?f=%5Ccos%20x%20%3D%20-%5Cfrac%7B1%7D%7B2%7D)
⇒
The solution set: ![\{0^{\circ}, 120^{\circ} , 240^{\circ}\}](https://tex.z-dn.net/?f=%5C%7B0%5E%7B%5Ccirc%7D%2C%20120%5E%7B%5Ccirc%7D%20%2C%20240%5E%7B%5Ccirc%7D%5C%7D)
Therefore, the solution for the given equation
is, ![0^{\circ}](https://tex.z-dn.net/?f=0%5E%7B%5Ccirc%7D)