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3 years ago

Find x and y. Please help this is on a test!!!

Mathematics

2 answers:

Helen [10]3 years ago

8 0

Answer:

y = 12 degrees

x = 40 degrees

Step-by-step explanation:

Triangle BDE: 3y + 54 + 90 = 180

3y + 144 = 180

3y = 36

y = 12

Line AC: angles on a straight line = 180

116 + 54 = 170

so, angle EBC = 10

Triangle BCE: 10 + 90 + 2x = 180

100 + 2x = 180

2x = 80

x = 40

ozzi3 years ago

6 0

To find the x-intercepts algebraically, we let y = 0 y=0 y=0 in the equation and then solve for values of x. In the same manner, to find for y-intercepts algebraically, we let x = 0 x=0 x=0 in the equation and then solve for y.

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Please help due tomorrow show work

Tju [1.3M]

Little help a negative times a negative is always a positive so the answer is 24 and another hint is a negative times a positive is a negative

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3 years ago

Solve this problem for n: 5/6 n=10 please show the work

umka21 [38]

5/6 n = 10

5n = 10*6

5n = 60

n = 60/5

n = 12

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3 years ago

Which expression is equivalent to

bazaltina [42]

Answer:

Step-by-step explanation:

6m+9q-3mq+4m= 10m + 9q - 3mq = C

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3 years ago

Read 2 more answers

If f(x) = 3x22, evaluate afI: ()k=1

Korolek [52]

Step 1: Write out the function given

$f(x)=3x^2-x$

Step 2: Interprete the question given

$\sum ^5_{k\mathop=1}f(\frac{k}{2})$

The question requested we find the summation of the first five terms for f(k/2), when k is 1, 2, 3, 4, and 5

Step 3: Find the expression for f(k/2)

$\begin{gathered} f(\frac{k}{2})=3(\frac{k}{2})^2-\frac{k}{2} \\ =\frac{3k^2}{4}-\frac{k}{2} \\ =\frac{3k^2-2k}{4} \end{gathered}$ $\begin{gathered} =\frac{3(1)^2-2(1)}{4}+\frac{3(2)^2-2(2)}{4}+\frac{3(3)^2-2(3)}{4}+\frac{3(4)^2-2(4)}{4}+\frac{3(5)^2-2(5)}{4} \\ =\frac{1+8+21+40+65}{4} \\ =\frac{135}{4} \\ =33.75 \end{gathered}$

Hence, the answer is 33.75

5 0

1 year ago

B(n)=1 (-2)^n-1<br> What is the 4th term in the sequence

zzz [600]

Answer:

The fourth term of the sequence B(4) =-8

The sequence is 1,-2,4,-8...

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the sequence

B(n) = 1(-2)ⁿ⁻¹

Put n=1

B(1) = 1(-2)¹⁻¹ = 2⁰ =1

Put n=2

B(2) = 1(-2)²⁻¹ = (-2)¹ =-2

Put n=3

B(3) =1(-2)³⁻¹ = (-2)² =4

Put n=4

B(4) = 1(-2)⁴⁻¹ =(-2)³ =-8

The sequence

1,-2,4,-8...

5 0

3 years ago