Select all the numbers that are solutions to the equation x3 = 27. A 27−−√ B 3 C 27−−√3 D 273 E 9

marta [7]

2/6 is also equal to 1/3. This is because the GCF of 2 and 6 is 2, and dividing both the numerator and denominator by 2 gets us a simplified fraction of 1/3.

:)

3 0

4 years ago

Read 2 more answers

Which is the simplified form of m^-8p^0

kipiarov [429]

Answer:

1 /m ^8

Step-by-step explanation:

Hope this helps

5 0

3 years ago

Read 2 more answers

Jordan is 12 years older than Anna. The

user100 [1]

9514 1404 393

Answer:

J = [12] +A
J + A = [50]

Step-by-step explanation:

If Anna's age is represented by A, then 12 more than Anna's age will be ...

12 + A

Jason's age is said to be 12 more than Anna's age, so ...

J = 12 + A

__

The sum of their ages will be J + A. That is said to be 50, so ...

J + A = 50

_____

These equations can be solved by using the first to substitute for J in the second.

(12 +A) +A = 50

2A = 38 . . . . . . . . subtract 12

A = 19 . . . . . . . . . . divide by 2

J = 12 +19 = 31 . . . find Jason's age

Jason is 31; Anna is 19.

4 0

3 years ago

You gave the server at a restaurant a 22% tip and ended up paying $41.48. What was the price of your meal before you applied the

const2013 [10]

Answer: The price of meal before the tip = $34.

Step-by-step explanation:

Given : The percentage of tip = 22% = 0.22 ( we divide a percentage by 100 to convert it into decimal)

Total amount paid ( including tip) = $41.48

Formula for Total bill = Price of meal + Tip amount , where Tip amount= 22% of Price of meal.

Let x be the price of meal, then

Total bill =x + 0.22 x (x )

⇒ $41.48= x(1+0.22) [ By distributive property]

⇒ $41.48 = x (1.22)

⇒ x= ($41.48) ÷ 1.22

⇒ x= 34

Hence, the price of your meal before you applied the tip = $34.

7 0

4 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

3 years ago