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3 years ago

Where on a check should you write the name of the payee? A. part A B. part B C. part C

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

7 0

Answer:

Part a - on the line where it says pay to the order of

Step-by-step explanation:

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Please help its due in 1 hour it would be best if you show work

aleksley [76]

Answer:

1:quadrant 1

2:quadrant 1

3:quadrant 2

4:quadrant 3

5:quadrant 1

6:quadrant 4

7:Z and quadrant 2

8: F and quadrant 1

9:A and quadrant 4

10: R and quadrant 4

11: N and quadrant 2

12: Q and quadrant 3

13a:the clock

13b:wonder wheel

13c:big coaster

13d: -1,2

Good luck

6 0

3 years ago

Darla has four buckets shaped like cylinders she is filling the buckets with water by using a scoop shaped like a cone if the co

padilas [110]

Answer:

12 Scoops

Step-by-step explanation:

Darla has 4 Cylinder Shaped Buckets

Volume of the Cylinders $=4*\pi r^2h$

The scoop is cone shaped and:

Volume of the Cone Scoop $=\frac{1}{3} \pi r^2h$

Since the radius and height of the cone scoop and cylindrical buckets are the same,

The number of Cone Scoops it will take to fill the buckets is:

Total Volume of Buckets/Volume of Cone Scoops

$=\dfrac{4*\pi r^2h}{\frac{1}{3} \pi r^2h} \\=4 \div \frac{1}{3}\\=12$

It will take 12 Scoops to fill the 4 buckets.

5 0

3 years ago

I dont understand this at all. I really need help!

Westkost [7]

Hello!

$\large\boxed{x^{4}}$

Recall that:

$\sqrt[z]{x^{y} }$ is equal to $x^{\frac{y}{z} }$ . Therefore:

$\sqrt[3]{x^{2} } = x^{\frac{2}{3} }$

There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

$(x^{\frac{2}{3} })^{6} = x^{\frac{2}{3}* 6 } = x^{\frac{12}{3} } = x^{4}$

3 0

3 years ago

An airplane traveled 108 miles in 20 minutes? How long will it take to fly 162 miles?

satela [25.4K]

Answer:

poopy

Step-by-step explanation:

Tee Hee

7 0

3 years ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago