10 ≤ x ≤ 30, x < 2y, x < 40.
Solution:
Given x is the number of graphing calculators produced daily and
y is the number of scientific calculators produced daily.
Step 1: A company produce atleast 10 and not more than 30 graphing calculators per day.
⇒ 10 ≤ x < 30
Step 2: Each day, the number of graphing calculators cannot exceed twice the number of scientific calculators produced.
⇒ x < 2y
Step 3: The number of scientific calculators cannot exceed 40 per day.
⇒ x < 40
Hence, the constraints are 10 ≤ x ≤ 30, x < 2y, x < 40.
Using the recurrence relation, we can find a couple more values in the sequence:
- a3 = 3a2 -3a1 +a0 = 3(4) -3(2) +2 = 8
- a4 = 3a3 -3a2 +a1 = 3(8) -3(4) +2 = 14
First differences are 0, 2, 4, 6, ...
Second differences are constant at 2, so the function is quadratic.
The sequence can be described by the quadratic ...
... an = n² -n +2
_____
We know the value for n=0 is 2, so we can find <em>a</em> and <em>b</em> using the given values for a1 and a2.
... an = an² +bn +2
... a1 = 2 = a·1² +b·1 +2 . . . . for n=1
... a + b = 0
... a2 = 4 = a·2² -a·2 +2 . . . . for n = 2; using b=-a from the previous equation
... 2 = 2a
... a = 1 . . . . so b = -1
Answer:
25 days old
Step-by-step explanation:
7 days = 1 week
3 x 7 = 21
21 + 4 = 25
25 days old
J = 506
J needs to be isolated so add 263 to both sides. -263 is cancelled out and 263 + 243 is 506.
Hence the answer of 506
This is really weird.
-- NONE of the situations matches the equation at the top.
-- And the equation at the top isn't even really any big deal . . .
it's <em>always</em> true, no matter what ' t ' is . If you remove all of
the parentheses and simplify it, it says that 6 = 6. Well duh !
