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krok68 [10]
3 years ago
10

A plane rises from take-off and flies at an angle of 8° with the horizontal runway. When it has gained 850 feet, find the distan

ce to the nearest foot, the plane has flown.
850 ft

The plane has flown approximately ___ feet. (Round to the nearest foot.)
Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

C\approx 5748.2feet

Step-by-step explanation:

From the question we are told that

Angle of elevation \thata=8 \textdegree

Height of plane H=850feet

Generally the equation for the Distance flown is given by

   C=\frac{H}{sin \theta}

   C=\frac{800}{sin8}

   C=5748.237227

   C\approx 5748.2feet

Therefore Distance flown is

   C\approx 5748.2feet

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3 years ago
A particular sawdust pile has a base diameter of 25 feet when the height is 20 feet. Find the volume of this sawdust pile when i
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The volume of the sawdust pile is 11,039.06 ft³.

<h3>What is the volume of the pile?
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The shape of the sawdust pile would be a cone. The diameter is always proportional to its height.

Diameter = k x height

where k is equivalent to the rate of increase of the diameter with respect to the increase in height.

25= k20

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Diameter when height is 30 ft = 1.25x 30 = 35.50 feet

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\frac{1}{3} x 3.14 x 18.75² x 30 = 11,039.06 ft³

To learn more about the volume of a cone, please check: brainly.com/question/13705125

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