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3 years ago

Find the GCF of each set of trinomials 60x^2y^2 , 35xz^3

Mathematics

2 answers:

gladu [14]3 years ago

5 0

$GCF(60x^2y^2;\ 35xz^3)=5x$

Vedmedyk [2.9K]3 years ago

4 0

I look at the similarities in factors then write them down. So 60 and 35, they have 5 (highest factor possible) in common. Now look at the variables. The only thing they have in common are the x's, and the second one doesn't have ^2, so its just x. That's how I got the final answer as 5x

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Financial Literacy Paul earns $25 for grooming a dog plus $18.50

Free_Kalibri [48]

Answer:

e): m=18.50d + 25

Step-by-step explanation:

3 0

3 years ago

I need help on this.

diamong [38]

Answer:

hello

Thanh have 3,5 meters of fabric. i can say

3,5/1 for it.

and i can say 35/10

now he used three-fourths of a meter of fabric.

its equal to 3/4

now i have to remove 3/4 from 35/10.

35/10 - 3/4

denominators have to be same thats why im expanding them to 20.

35×2/10×2 = 70/20

3×5/4×5 = 15/20

now i can remove 15/20 from 70/20!

70/20 - 15/20 = 55/20

we cannot see 55/20 in the options.

thats why im dividing them with 5.

55÷5= 11 20÷5=4

the answer is 11/4

11/4 = 2and 3/4

so its option 2

good luck(:

7 0

3 years ago

A number with a negative exponent can always be written using positive exponents in fraction form. the numerator will always be

Elena-2011 [213]

Answer:

Step-by-step explanation:

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8 0

3 years ago

Please answer the question below

Maurinko [17]

Answer:

The rate of change in the submarine's elevation is 26.0 feet per second.

Step-by-step explanation:

She begins 151 feet below sea level

Thus, her initial point is y₁ = 151 feet below sea level

i.e. at t₁=0 seconds, y₁ = 151 feet below sea level

After descending for the 3 seconds, she is 229 feet below sea level.

Thus, her second point is y₂ = 229 feet below sea level after 3 seconds

i.e. at t₂=3 seconds, y₂ = 229 feet below sea level

The rate of change is basically the slope. Thus, the rate of change can be obtained by taking the slope.

slope = rate of change = (y₂ - y₁)/(t₂ - t₁)

= (229 - 151) / (3 - 0)

= 78/3

= 26.0

Therefore, the rate of change in the submarine's elevation is 26.0 feet per second.

6 0

3 years ago

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

$= 0.92 -0.24\\\\= 0.68$

6 0

3 years ago