Identify a pair of vertical angles in the figure.

WILL MARK BRAINIEST!!1 PLZ HELP!25 points!!! The coordinate grid shows points A through K. What point is a solution to the syste

marishachu [46]

Answer:

A, C, D and K

Step-by-step explanation:

Inequalities:

y ≤ −2x + 10 and y >1/2x-2

<u>Finding zeros for the first inequality:</u>

x=0 ⇒ y= 10, point (0, 10)
y=0 ⇒ x= 5, point (5, 0)

Locating these 2 points and connecting to get the first line.

Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.

<u>Finding zeros for the second inequality:</u>

x=0 ⇒ y= -2, point (0, -2)
y= 0 ⇒ x= 4, point (4, 0)

Locating these points and connecting to get the second line.

Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.

Now we have the space of intersection of the above inequalities.

So the points in same section are the solution.

They are:

Points A, C, D and K

See attached for explanation

7 0

4 years ago

Help please..........

Elodia [21]

(-7,1)
Hope this helps!

6 0

3 years ago

Read 2 more answers

Simplify square root of five times square root of eight

Andrej [43]

Answer:

2square root 10

Step-by-step explanation:

calculator

6 0

3 years ago

the lighthouse is 76 feet tall and has 99 stairs. an ocean liner is 3 times as tall as the lighthouse. what is the extra informa

QveST [7]

The answer to that problem is 100 feet tall

3 0

4 years ago

Read 2 more answers

A skateboarder goes off of a ramp at a speed of 52 ft./s. The ramp is 5 ft. above the ground with a 30°

kenny6666 [7]

Answer:

We need an equation for the horizontal motion and another for the vertical motion.

First, let's look at the vertical motion.

Once the skateboarder is on the air, the only force acting on him/her will be the gravitational force, then the vertical acceleration is the gravitational acceleration.

Ay(t) = -32ft/s^2

Where the negative sign is because this acceleration pulls down the skateboarder.

To get the vertical velocity, we need to integrate over time, so we get:

Vy(t) = (-32ft/s^2)*t + v0

Where v0 is the vertical velocity.

To know the vertical velocity, we use the fact that:

When the skateboarder jumped, the velocity was 52ft/s, and the angle was 30°.

Then the initial velocity in the y-axis (the vertical one) as:

Vy = 52ft/s*sin(30°)

and the initial velocity on the x-axis is:

Vx = 52ft/s*cos(30°)

Replacing that in the vertical velocity equation:

Vy(t) = (-32ft/s^2)*t + 52ft/s*sin(30°)

We need to integrate again to get the position equation:

Py(t) = (1/2)*(-32ft/s^2)*t^2 + 52ft/s*sin(30°)*t + p0

Where p0 is the initial vertical position, this would be the height of the ramp, which is 5ft

Then the equation of the vertical motion is:

Py(t) = (1/2)*(-32ft/s^2)*t^2 + 52ft/s*sin(30°)*t + 5ft

For the horizontal motion, we don't have any force, then the acceleration is:

Ax(t) = 0

The velocity is:

Vx(t) = 52ft/s*cos(30°)

And the position equation is:

Px(t) = 52ft/s*cos(30°)*t + p0

Where p0 is the initial horizontal position, we can assume that is zero, then:

Px(t) = 52ft/s*cos(30°)*t

Then the two equations that represent the skater jump are:

Py(t) = (1/2)*(-32ft/s^2)*t^2 + 52ft/s*sin(30°)*t + 5ft

Px(t) = 52ft/s*cos(30°)*t

6 0

3 years ago