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Sloan [31]
2 years ago
9

(1/3)^x^1/4 • (1/3)^x^2/3

Mathematics
1 answer:
monitta2 years ago
5 0
Wait i’m confused on how this equation is modeled i’m sorry do you have a picture? i wanna be sure i answer this right.
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I need to know the distance and if your could please tell me the formula for future problems thank you!! ASAP
Ksivusya [100]

Distances in 2- and 3-dimensions (and even higher dimensions) can be found using the Pythagorean theorem. The straight-line distance can be considered to be the hypotenuse of a right triangle whose sides are the horizontal and vertical differences between the coordinates.

Here, you have A = (0, 0) and B = (3, 6). The horizontal distance between the points is ...

... 3 - 0 = 3 . . . . the difference of x-coordinates

The vertical distance between the points is ...

... 6 - 0 = 6 . . . . the difference of y-coordinates

Then the straight-line distance (d) between the points is found from the Pythagorean theorem, which tells you ...

... d² = 3² + 6²

... d = √(9 + 36) = √45 ≈ 6.7 . . . units

8 0
3 years ago
Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
natka813 [3]

Suppose that the height (in centimeters) of a candle is a linear function of

the amount of time (in hours) it has been burning.

Let x be the amount of time in hours

Let y be the heoght of a candle in centimeters

The two points are then as (9,24.5) and (23,17.5).

\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(9,\:24.5\right)\mathrm{,\:}\left(23,\:17.5\right)

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(9,\:24.5\right),\:\left(x_2,\:y_2\right)=\left(23,\:17.5\right)

m=\frac{17.5-24.5}{23-9}

m=-0.5

\mathrm{Plug\:the\:slope\:}-0.5\mathrm{\:into\:}y=mx+b

y=\left(-0.5\right)x+b

\mathrm{Plug\:in\:}\left(9,\:24.5\right)\mathrm{:\:}\quad \:x=9,\:y=24.5

24.5=\left(-0.5\right)\cdot \:9+b

24.5=\left(-0.5\right)\cdot \:9+b

-4.5+b=24.5

b=29

\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=-0.5\mathrm{\:and\:}\mathbf{b}=29

y=-0.5x+29

Now plug in x=21, we get

y=-0.5*21+29=18.5

Thus the height of the candle after 21 hours is 18.5 centimeters.

7 0
3 years ago
Your boss gave you a raise. Your weekly salary went from $375 to $450. What was your percent raise?
Yuri [45]
<span>1. Find the difference
2. Divide the difference by the original number it went up from.
</span>
450-375 = 75

75/375 = 0.2

You got a 20% raise.

Proof:
375*.2 = 75
375+75 = 450
3 0
2 years ago
Clayton says that 2 1/2 + 3 3/5 will be more than 5 but less than 6 since 2 + 3 is 5. Is Clayton’s reasoning correct? Prove him
antoniya [11.8K]
He is wrong...

2 1/2 + 3 3/5 = 97/20

Simplified, I believe the answer is 4 17/20
7 0
3 years ago
In the book,the distance between two planets is given as 4.07×10^¹² kilometres. The speed of light is 1.1×10^⁹ kilometres per ho
Sphinxa [80]

Answer:

3700hours

154days

Step-by-step explanation:

Speed can be defined as the distance cover per time, it can be expressed as

Speed= distance/ time........eqn(1)

Given:

distance between two planets= 4.07×10^¹²

speed of light = 1.1×10^⁹ kilometres per hour

Time= ??

Then substitute the values into equation (1) we have

Speed= distance/ time

1.1×10^⁹ kilometres per hour= 4.07×10^¹²kilometre/ time

Cross multiply, we have

Time= (4.07×10^¹²kilometre) /(1.1×10^⁹ kilometres per hour)

Time= 3700hours.

To convert to day, we know that

60 minute= 1hour

24hour=1day

Time= (3700hour×1day)/24hour

Time= 154days approximately.

Hence, the time taken for light to travel from one of these planets to the other is 154days or 3700hours

7 0
3 years ago
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