a rectangle has a perimeter of 22 feet. the width is 5 feet less than the length. find the length and width of the rectangle
1 answer:
Answer:
the length is 8ft
the width is 3ft
Step-by-step explanation:
Step one:
given
perimter= 22ft
let the length be x
width = x-5
Step two
the expression for the perimeter of a rectangle is
P=2L+2W
substituting our data
22= 2(x)+2(x-5)
open brackets
22=2x+2x-10
collect terms and solve for x
22+10=4x
32=4x
divide both sides by 4
x= 32/4
x= 8ft
the length is 8ft
the width = x-5= 8-5= 3ft
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Hope this helps, good luck! :)
