Cost of the admission tickets: 11.75x
Cost of the box lunch: 5x
Expressions to find the total cost = (1) ....... 11.75x + 5x
That is equivalent to: (2) .......... (11.75 + 5)x = 16.75x.
Now calculate the cost for x = 5 using both expressions:
1) 11.75(5) + 5(5) = 58.75 + 25 = 83.75
2) 16.75(5) = 83.75
Of course you got the same result with both expressions.
(4/5) / 6 =
4/5 * 1/6 =
4/30 =
2/15....each person gets 2/15 lb of peanuts
<em>y</em> - 1/<em>z</em> = 1 ==> <em>y</em> = 1 + 1/<em>z</em>
<em>z</em> - 1/<em>x</em> = 1 ==> <em>z</em> = 1 + 1/<em>x</em>
==> <em>y</em> = 1 + 1/(1 + 1/<em>x</em>) = 1 + <em>x</em>/(<em>x</em> + 1) = (2<em>x</em> + 1)/(<em>x</em> + 1)
<em>x</em> - 1/<em>y</em> = <em>x</em> - (<em>x</em> + 1)/(2<em>x</em> + 1) = (2<em>x</em> ² - 1)/(2<em>x</em> + 1) = 1
==> 2<em>x</em> ² - 1 = 2<em>x</em> + 1
==> 2<em>x</em> ² - 2<em>x</em> - 2 = 0
==> <em>x</em> ² - <em>x</em> - 1 = 0
==> <em>x</em> = (1 ± √5)/2
If you start solving for <em>z</em>, then for <em>x</em>, then for <em>y</em>, you would get the same equation as above (with <em>y</em> in place of <em>x</em>), and the same thing happens if you solve for <em>x</em>, then <em>y</em>, then <em>z</em>. So it turns out that <em>x</em> = <em>y</em> = <em>z</em>.
Answer:
c=50
Step-by-step explanation:
