Mrs. Wheeler had a bowl of M&M’s sitting on her table. Her daughter Lauren told her that she thought there were 100 M&M’

Question

2 years ago

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Mrs. Wheeler had a bowl of M&M’s sitting on her table. Her daughter Lauren told her that she thought there were 100 M&M’

s in the bowl. They decided to count them to see if Lauren was correct. There were actually 75 What was her percent error rounded to the nearest tenth?

Mathematics

1 answer:

laiz [17] · Answer 1 · 2022-06-30T19:45:03+03:00

There was 33.3% error in her calculation.

Step-by-step explanation:

Approx value thought by Lauren = 100

Exact value counted = 75

Percent error = $\frac{|approx-exact|}{exact}*100$

$Percent\ error=\frac{|100-75|}{75}*100\\\\Percent\ error=\frac{|25|}{75}*100\\\\Percent\ error=\frac{2500}{75}\\\\Percent\ error=33.33\%$

Rounding off to nearest tenth;

Percent error = 33.3%

There was 33.3% error in her calculation.

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