Answer:
1/52
Step-by-step explanation:
There is only one of each type of card in each suit.
P(card is a diamond) = 13/52
P(card is a diamond + king) = (13/52)×(1/13) = (13/676) = (1/52)
Answer:
Step-by-step explanation:
win
There are 3 face cards / suit. Every suit contains a Jack, Queen, and king.
There are 4 suits so the number of face cards is 3*4 = 12
There is 1 ace / suit
There are 4 suits so the number of aces is 1 * 4 = 4
The gain from the face cards = 12 * 13 = 156
The gain from the aces = 4 * 3 = 12
Total gain = 168
Losses
Any other card costs you $5
How many cards is that? 52 - 16 = 36
Each one costs 5 dollars
Total loss = 5 * 36 = 180
So each time you play the game, you can expect to lose 180 - 68 = 12 dollars. You should walk away quickly from this one.
Given linear equation in standard form x-y=-2.
Let us convert it in slope-intercept form first.
x-y =-2.
Subtracting x from both sides
x-x-y = -2-x
-y = -x-2.
Dividing both sides by -1, we get
y= x+2.
We can write it as y=1x+2.
Let us compare it with slope-intercept form y=mx+b.
On comparing, we get slope m= 1 and y-intercept b=2.
Let us check option -3x+3y=6.
Let us check it by converting in slope-intercept form.
Adding 3x on both sides we get
-3x+3x+3y=6+3x
3y = 3x + 6.
Dividing both sides each term by 3.
3y/3 = 3x/3 + 6/3.
y= 1x +2.
On comparing with slope-intercept form y=mx+b.
We got slope m=1 and y-intercept =2.
So, the equation in option B) -3x+3y=6 create a consistent and dependent system with x-y=-2.
Answer: The theoretical probability of the coin landing heads up is 0.7
Step-by-step explanation:
Hi, to answer this question we simply have to divide the number of times that the coin lands heads up (42 times) by the number of times that the coin was flipped:
Mathematically speaking:
42 /60 = 0.7 (decimal form)
The theoretical probability of the coin landing heads up is 0.7
For the or percentage form we simply multiply the result by 100:
0.7 (100) = 70%
Feel free to ask for more if needed or if you did not understand something.
Answer:
The position of the concrete relative to its initial position is 4ft behind its initial position
Step-by-step explanation:
Let us analyze the problem following the sequence of events.
First of all, the crane is initially 7 ft from the back of the truck.
Once the truck drives away, the crane lowers the concrete at 11 ft away from the back of the truck.
To get this distance relative to the initial position, we have to subtract the initial position from the final position of the concrete.
This will be
11ft - 7ft = 4 ft
The position of the concrete relative to its initial position is 4ft behind its initial position
