15 minutes= 2 problems
75 / 15 = 5
2 x 5 = 10 problems
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60
Answer:
a*(1 -0.5)*(1 +0.5) = 0.75a . . . . the original number "a" is larger
(a/(0.75a) -1) * 100% = 33 1/3% . . . . the original number is larger by 33 1/3% of the revised number
Step-by-step explanation:
Answer:
78 novels
Step-by-step explanation:
N= novels
M= month
6N = 1M
? = 13M
6N × 13M= 78NM
78NM ÷ 1M
cancel M, therefore;
the number of novels Usama needs to read in 13 months is 78.
Answer:
%65
Step-by-step explanation: