This is a geometric sequence of the form:
a(n)=ar^n, a=initial value, r=common ration, n=term number, if we relabel it for h(b) we have
h(b)=14(0.8^b)
h(3)=14(0.8^3)
h(3)≈7.2 ft (to nearest tenth of a foot)
Answer: I believe the answer is 800 students
Step-by-step explanation:
1. Find a LCM to use to compare fractions
1/8 = 5/40
2/10= 8/40
Now you can see that 2/10 is clearly bigger.
Hope this helps!
I can't see the picture, are you able to repost it
