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lyudmila [28]
4 years ago
6

Solve the quadratic equation 3x^2 +x-5=0 Give your answer to 2 decimal places

Mathematics
1 answer:
Firdavs [7]4 years ago
5 0

This quadratic should be solved using the quadratic formula.

 

The quadratic formula is

 

(-b +/- sqrt(b2 - 4ac)) / (2a)       (Side note: The +/- means that you use the plus sign once, then recalculate again using the minus sign. You should get two answers this way.)

 

The numbers that we plug into the letters can be found from the general form of a quadratic equation

 

ax2 + bx + c

 

In your quadratic a = 3, b = 1, and c = -5. I'll let you try and solve the rest on your own. Whatever your answer is, round it off to two decimal places.

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Ierofanga [76]

n ∈ natural even numbers

Step-by-step explanation:

1 + 3 + 5 + 7 + … + (2n-1)

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sum of the first n terms :

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Sₙ = n/2(1 + 2n - 1)

Sₙ = n/2(2n)

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Answer:

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Step-by-step explanation:

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2x+47-2x =7x -2x+2

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Divide by 5

45/5 =5x/5

9 =x

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