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lyudmila [28]
4 years ago
6

Solve the quadratic equation 3x^2 +x-5=0 Give your answer to 2 decimal places

Mathematics
1 answer:
Firdavs [7]4 years ago
5 0

This quadratic should be solved using the quadratic formula.

 

The quadratic formula is

 

(-b +/- sqrt(b2 - 4ac)) / (2a)       (Side note: The +/- means that you use the plus sign once, then recalculate again using the minus sign. You should get two answers this way.)

 

The numbers that we plug into the letters can be found from the general form of a quadratic equation

 

ax2 + bx + c

 

In your quadratic a = 3, b = 1, and c = -5. I'll let you try and solve the rest on your own. Whatever your answer is, round it off to two decimal places.

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X+y=3<br> y+x= 5<br><br> help please
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Solve by elimination ie eliminate x or y from the equations by performing operations on them.
first label the equations , to follow the process.
x - y = 5 ----------------(1)
x+ y = 3 ----------------(2)
If (1) and (2) are added then y will be eliminated.
(1) + (2) gives : 2x = 8 → x = 4
now substitute this value of x into either of the 2 equations and solve for y.
let x = 4 in (1) : 4 - y = 5 → -y = 1 → y = -1
check in (1) : 4-(-1) = 4+1 = 5
check in(2) : 4 - 1 = 3


So your answer is x = 4 , y = -1
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