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tekilochka [14]
3 years ago
8

Pls pls pls pls helpppp it's 12:10am

Mathematics
1 answer:
andriy [413]3 years ago
6 0

Answer:

I guess it will be (D) 4/3=$4.41/x

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Suppose s varies directly with t. When t27, s=3. What is s when t=632
jekas [21]

Answer:

G 7

Step-by-step explanation:

If t= 27 when s=3  27/3=9

the t=63 when s= 7    63/7= 9

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Gianna invested $30,000 in an account paying an interest rate of 1.9% compounded
Ganezh [65]

Answer:

5,095,068

Step-by-step explanation:

The equation for this problem is x^y * z where x is the percentage, Y is the number of years, and Z is the original deposit. Multiply 1.9^8 * 30,000 which becomes; 5,095,068.

Whoever has that bank account is going to be very rich.

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How do I find the perimeter of this ?
gavmur [86]

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26 is the perimeter

Step-by-step explanation:

you add all of the side numbers just like this:

9+5+12= 26 :)

     Hope this helped :D

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3 years ago
Find the missing angle..? x=?
Sedaia [141]

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x = 95°

Step-by-step explanation:

x and 95 are vertical angles and congruent, thus

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3 years ago
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A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0
3 years ago
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