Let daniel's age = d and let jessica's age = j
let your current age = x and your wife's current age = y
x = 5d (given in question)
∴ x - 5d = 0
x + 21 = 2(d+21) (given in question)
∴ x + 21 = 2d + 42
∴ x - 2d = 21
We can solve these two rearranged equations simultaneously by multiplying the first equation by -1 and adding them. This gives us the following:
3d = 21
∴ d = 7
This means that daniel is currently 7 and (if we substitute d = 7 into one of the equations) you are 35. We use a similar method for your wife's and jessica's current ages.
y = 7j (given in question)
∴ y - 7j = 0
y + 8 = 3(j + 8)
∴y + 8 = 3j + 24
∴ y - 3j = 16
If we use a similar method of elimination we get this:
4j = 16
∴ j = 4
Hence, from this we can concur that daniel is 7 and jessica is 4.
The h30 of 1x10 Ig is 1x34
Answer:
Only one because if it's every 58 miles the next one would be at 116 miles which is higher than 75
Total number of bulbs produced=5000
total number of samples=120
number of defective=3
Probability that a bulb selected at random is defective will be:
3/120=0.025
The total number of bulbs that could be defective out of 5000 bulbs produced will be:
5000(0.025)=125 bulbs
Answer:
simple
Step-by-step explanation:
t=b×h/2 and p= b×h
