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KonstantinChe [14]
3 years ago
13

It is Keke’s birthday, and her parents want to surprise her with a room full of balloons. Use the Fermi process

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Answer:

im not sure sorry .

Step-by-step explanation:

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Hey guys can you answer this one question real quick
Umnica [9.8K]

Answer:

a. 1/5

b. (3, 3/5)

c. 1/5x = y

Step-by-step explanation:

Remember: (x, y)

0.5 = 1/2

(1/2, 1/10) = 1/10 ÷ 1/2 = 1/10 • 2 = 1/5, you can divide y/x = constant of proportionality. 1/10 ÷ 1/2.

1 2/5 = 7/5

(7, 7/5) = 7/5 ÷ 7 = 7/5 • 1/7 = 1/5, y/x = constant of proportionality. 7/5 ÷ 7.

  • a. 1/5 is the constant of proportionality
  • b. (3, 3/5) because 3/5 ÷ 3 or 3/5 • 1/3 = 1/5.
  • c. 1/5x = y

6 0
3 years ago
A marketing company is designing a new package for a box of cereal. They have determined that the function C(x) = 4.5 x2 models
Vlad1618 [11]

So the function is

\\ \rm\rightarrowtail y=4.5x^2

As we know

  • x²≥0
  • x≥0

hence domain is

\\ \rm\rightarrowtail D_f\in R

  • Least value of function is at x²=0 i.e 0

Hence range:-

\\ \rm\rightarrowtail R_f\in [0,\infty)

6 0
2 years ago
Which expression has the same value as -5, + (-4)?
marissa [1.9K]
First row, the answer on the left , -5 3/4 - 4 2/3
3 0
3 years ago
If the Alexanders completed the 735 mile trip in 15 hours, what was their average rate of travel?
Darina [25.2K]
The rate of travel here is in mph - "miles per hour".

That just means how many miles you can travel in one hour. In this problem, you're given 15 hours, and the distance they travel within those 15 hours.

Therefore, you should divide both the number of miles and the number of hours by 15 to find out how far they can travel in 1 hour.

735 ÷ 15 = 49 miles
15 ÷ 15 = 1 hour

Their average rate of travel was 49 miles in 1 hour, which is 49 mph.

6 0
3 years ago
Read 2 more answers
Find the distance between (-3, 11) and (-6,4).Round to the nearest then the
Likurg_2 [28]

Answer:

d =7.6

Step-by-step explanation:

(-3,11) =(x_1,y_1)\\(-6,4)=(x_2,y_2)\\\\\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\=\sqrt{\left(-6-\left(-3\right)\right)^2+\left(4-11\right)^2}\\= \sqrt{(-6+3)^2+(4-11)^2}\\ \\d= \sqrt{(-3)^2+(-7)^2} \\\\d = \sqrt{9+49}\\ \\d = \sqrt{58}\\\\d = 7.61577\\\\d =7.6

3 0
3 years ago
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