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3 years ago

What is the measure of CED

Mathematics

2 answers:

Nataly_w [17]3 years ago

5 0

Answer:

The measure of CED is p degree.

Step-by-step explanation:

In triangle ABC and EDC,

$\angle ABC=\angle EDC=70^{\circ}$ (Given)

$\angle ACB=\angle ECD$ (Vertical opposite angles)

By AA rule of similarity,

$\triangle ABC\sim \triangle EDC$

Corresponding angles of similar triangles are same.

$\angle CAB=\angle CED$

$p=\angle CED$

Therefore the measure of CED is p degree.

Aleks04 [339]3 years ago

3 0

110? It's a supplementary angle.

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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6. Assume that a component passes a test is 0.85 and that components perform independently. What is the probability that the thi

Tanzania [10]

Answer:

3.90% probability that the third failure will occur on the tenth component tested

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that a component passes a test is 0.85

So they fail with probability of $p = 1 - 0.85 = 0.15$

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First 9 components: Two failures, that is, P(X = 2) when n = 9.

10th component: Failure with probability 0.15.

$P = 0.15P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

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$P = 0.15P(X = 2) = 0.15*0.2597 = 0.0390$

3.90% probability that the third failure will occur on the tenth component tested

5 0

3 years ago