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astraxan [27]
3 years ago
5

6) The sum of three consecutive numbers is 120. What is the smallest of the three numbers ?

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0

Answer:

39

Step-by-step explanation:

Let the smallest number be n,

then the three numbers are n, n+1 and n+2

Therefore, n+(n+1)+(n+2)=120

Collecting like terms,

n+n+n=120-1-2

3n=117

n=117/3

n=39

Therefore the numbers are 39,40 and 41.

And the smallest number is 39.

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The times 1 slope is implied, so you could also write it as: 
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3 years ago
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faust18 [17]

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Answer:

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Step-by-step explanation:

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