3 years ago

6) The sum of three consecutive numbers is 120. What is the smallest of the three numbers ?

Mathematics

1 answer:

bekas [8.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

Let the smallest number be n,

then the three numbers are n, n+1 and n+2

Therefore, n+(n+1)+(n+2)=120

Collecting like terms,

n+n+n=120-1-2

3n=117

n=117/3

n=39

Therefore the numbers are 39,40 and 41.

And the smallest number is 39.

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