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3 years ago

PLSSS, NEED ANSWER. Find the midpoint of the line segment with end coordinates of (-2,-5 and 3,-2

Mathematics

1 answer:

gregori [183]3 years ago

3 0

Answer:

(0.5, -3.5)

Step-by-step explanation:

(x1 + x2/2, y1 + y2/2)

(-2 + 3 / 2, -5 - 2 / 2)

(1/2, -7/2)

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Will give 5 stars it's due soon helppp

Alenkinab [10]

Answer:

The answer is B

Step-by-step explanation:

Since -2/3 multiplied by 3 equals -2, all you need to do is -2+1 which equals -1 which is the same number y is supposed to be.

Hope this helps

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3 years ago

Read 2 more answers

Simplify following the order of operations

STatiana [176]

Answer:

52.09

Step-by-step explanation:

Follow the acronym PEMDAS (Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction) for order of operations problems.

1. Solve what is in parentheses. (9 - 7) = 2

48 ÷ 23 + 25 (9 - 7) = 48 ÷ 23 + 25 × 2

2. Divide. 48 ÷ 23 = 2.09

2.09 + 25 × 2

3. Multiply. 25 × 2 = 50

2.09 + 50

4. Add. 2.09 + 50 = 52.0

I know that 52.09 wasn't one of the options listed, but it is the exact answer. If you must choose one of those options, choose 50, since it is the closest.

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3 years ago

I found a place that will give me 20% discount if I spend over $50. My pill is $75 What is my final bill after the savings?

svlad2 [7]

75-20% = 60 hope I helped XD

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3 years ago

Read 2 more answers

What is the derivative of this function: F(x)=(5e^4x)+(e^-x^6)

Fed [463]

Answer:

$\dfrac{dF(x)}{dx} =20e^{4x}-6x^5e^{x^{-6}}$

Step-by-step explanation:

The derivative of $F(x)$ is calculated as follows:

$\dfrac{dF(x)}{dx}=\dfrac{d}{dx} [(5e^{4x})+(e^{-x^6})]$

$\dfrac{dF(x)}{dx}=\dfrac{d}{dx} [(5e^{4x})]+\dfrac{d}{dx} [(e^{-x^6})]$

$\dfrac{dF(x)}{dx}=5\dfrac{d}{dx} [(e^{4x})]+\dfrac{d}{dx} [(e^{-x^6})]$

using the chain rule we find that

$\dfrac{d}{dx} [(e^{4x})]= \dfrac{d}{d(4x)} [(e^{4x})]+ \dfrac{d}{dx} [4x] = 4e^{4x},$

$\dfrac{d}{dx} [(e^{-x^6})] = \dfrac{d}{d(-x^6)} [(e^{-x^6})]+\dfrac{d}{dx} [(-x^6})]= -6x^5e^{-x^6};$

therefore,

$\dfrac{dF(x)}{dx}=5\dfrac{d}{dx} [(e^{4x})]+\dfrac{d}{dx} [(e^{-x^6})] =5(4e^{4x})-6x^5e^{x^{-6}}$

$\boxed{\dfrac{dF(x)}{dx} =20e^{4x}-6x^5e^{x^{-6}}}$

8 0

3 years ago

SOLVE EACH EQUATION BY TAKING SQUARE ROOTS. 1.) 3(x-5)^2=48 2.)2x^2-56=42

Tom [10]

Answer:

see explanation

Step-by-step explanation:

(1)

3(x - 5)² = 48 ( divide both sides by 3 )

(x - 5)² = 16 ( take the square root of both sides )

x - 5 = ± $\sqrt{16}$ = ± 4 ( add 5 to both sides )

x = 5 ± 4

Thus

x = 5 - 4 = 1

x = 5 + 4 = 9

Solutions are x = 1, x = 9

(2)

2x² - 56 = 42 ( add 56 to both sides )

2x² = 98 ( divide both sides by 2 )

x² = 49 ( take the square root of both sides )

x = ± $\sqrt{49}$ = ± 7

Solutions are x = - 7, x = 7

4 0

3 years ago