Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
Answer:
1
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given the following in the question:
Quantity, q
Selling price in dollars per yard, p
Total revenue earned =
f(20)=13000
This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.
f′(20)=−550
This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.
We have to find R'(20)
Differentiating the above expression, we have,
Putting the values, we get,
Answer:
-13
Step-by-step explanation:
Given that:
Average temperature for a period of 4 days = - 8
Average temperature for a 5 day period = - 9
Temperature on the 5th day:
(total temp for the 4 days + 5th day temperature) / 5 = - 9
Let 5th day temperature = x
Total temperature for the 4 days = 4 * - 8 = - 32
(-32 + x) / 5 = - 9
-32 + x = - 45
x = - 45 + 32
x = - 13
4*m*3/3*m*2*n*x*9*n*2/30*m*2*n*2 evaluates to 96/5n^3m^3mx and that is the final answer.