Answer:
(x + 3) = 9/2
Step-by-step explanation:
Here, we want to write an equation to find the length of the rectangle 
Mathematically; 
Area of rectangle = length * breadth 
15 3/10 = (x + 3) * 3 2/5
(x + 3) = 15 3/10 divided by 3 2/5
(x + 3) = 153/10 * 5/17
(x + 3) = 9/2
 
        
             
        
        
        
The area of a rectangle is calculated my multiplying the length of the rectangle and the width of the rectangle. In this case, the length (the longer side) is 70 feet while the width (shorter side) is 30 feet. Hence the area is 2,100 ft2. 
        
             
        
        
        
Answer:
   
 
Step-by-step explanation:
From the question we are told that:
Area of Rectangle A=6183
Equation of Length
  
Where

Generally the equation for Area of Rectangle is mathematically given by
  
  
  
  
  
Therefore
  
   
 
 
        
             
        
        
        
Answer
44
Step-by-step explanation:
R = C/(2*Pi).
So, in order to find the radius from the circumference, you use the formula R = C/(2*Pi). In other words, just divide the circumference by 2 times pi.
 
        
             
        
        
        
Answer:
![\left[\begin{array}{ccc}3&-5  &|12\\4&-2  &|15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%20%20%26%7C12%5C%5C4%26-2%20%20%26%7C15%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
When making a matrix of two equations with the variables x and y, the result will be a matrix with three columns:
- a column for the values of x in each equation
- a column for the values of y in each equation
- a column for the independent values of each equation
since our system of equations is:

we can see that the value for x in the first equation is 3 and in the second equation is 4, thus the first column will have the numbers 3 and 4:
![\left[\begin{array}{ccc}3&&\\4&&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26%26%5C%5C4%26%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now for the values of y we hvae -5 in the first equation and -2 in the second equation, we update the matrix with another column with the values of -5 and -2:
![\left[\begin{array}{ccc}3&-5&\\4&-2&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%26%5C%5C4%26-2%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Finally, the last column is the independent values of each equation (or the results) in the first equation that number is 12 and in the second equation is 15, thus the matrix is:
![\left[\begin{array}{ccc}3&-5&12\\4&-2&15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%2612%5C%5C4%26-2%2615%5C%5C%5Cend%7Barray%7D%5Cright%5D)
usually there is a line separating the columns for the values of x and y, and the independent values: 
![\left[\begin{array}{ccc}3&-5  &|12\\4&-2  &|15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%20%20%26%7C12%5C%5C4%26-2%20%20%26%7C15%5C%5C%5Cend%7Barray%7D%5Cright%5D)
this is the matrix of the system of equations