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Makovka662 [10]

3 years ago

9

The diagram below is a net of a right triangular prism.

2 answers:

zloy xaker [14]3 years ago

6 0

Answer: the answer is B. 190.08 cm^2

Step-by-step explanation:

kap26 [50]3 years ago

3 0

Answer: The answer is B

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Please help I don’t understand this

maks197457 [2]

Answer:

1. Swim practice $\leq$ 35 laps

2. ran<5 miles

3. occupancy<437 people

im sorry i cant draw something else out for the other questions

Step-by-step explanation:

6 0

3 years ago

Find each product. <br> (x - 6)(x + 2)

emmainna [20.7K]

Answer:

x^2-4x-12

Step-by-step explanation:

(x-6)(x+2)=x^2-6x+2x-12=x^2-4x-12

6 0

3 years ago

Read 2 more answers

Amy and Sarah are twins. They have a younger brother who is 3 years younger.

Shkiper50 [21]

Answer: no, because you are subtracting the 3 rather than adding

Step-by-step explanation:

twins= x + x

brother= x-3

equation =2x + (x-3)

4 0

3 years ago

Let F = (2, 3). Find coordinates for three points that are equidistant from F and the y-axis. Write an equation that says P = (x

True [87]

Answer:

The equation that says P is equidistant from F and the y-axis is $P(x,y) =\left(1,\frac{3+y'}{2} \right)$ .

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

Step-by-step explanation:

Let $F(x,y) = (2,3)$ and $R(x,y) =(0, y')$ , where $P(x,y)$ is a point that is equidistant from F and the y-axis. The following vectorial expression must be satisfied to get the location of that point:

$F(x,y)-P(x,y) = P(x,y)-R(x,y)$

$2\cdot P(x,y) = F(x,y)+R(x,y)$

$P(x,y) = \frac{1}{2}\cdot F(x,y)+\frac{1}{2} \cdot R(x,y)$ (1)

If we know that $F(x,y) = (2,3)$ and $R(x,y) = (0,y')$ , then the resulting vectorial equation is:

$P(x,y) = \left(1,\frac{3}{2} \right)+\left(0, \frac{y'}{2}\right)$

$P(x,y) =\left(1,\frac{3+y'}{2} \right)$

The equation that says P is equidistant from F and the y-axis is $P(x,y) =\left(1,\frac{3+y'}{2} \right)$ .

If we know that $y_{1}' = -3$ , $y_{2}' = 0$ and $y_{3}' = 3$ , then the coordinates for three points that are equidistant from F and the y-axis:

$P_{1}(x,y) = \left(1,\frac{3+y_{1}'}{2} \right)$

$P_{1}(x,y) = (1,0)$

$P_{2}(x,y) = \left(1,\frac{3+y_{2}'}{2} \right)$

$P_{2}(x,y) = \left(1,\frac{3}{2} \right)$

$P_{3}(x,y) = \left(1,\frac{3+y_{3}'}{2} \right)$

$P_{3}(x,y) = \left(1,6 \right)$

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

7 0

3 years ago

-2/17x=10 what is the solution set?

puteri [66]

Answer:

x=-85

Step-by-step explanation:

7 0

3 years ago