First you do 3a^4(2b^6c^3)^2
=12a^4b^12c^6
Find the value of θ,
θ = arccos -8/9 = 152.734 deg
You can substitute this value for the requirement.
tan 152.734 = -0.51539
sin 152.734 = 0.45812
<span>3m^-2 3n^3
--------- = -----------
5n^-3 5m^2
hope it helps</span>