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andriy [413]
3 years ago
9

Answer the two questions below. THANKS!!

Mathematics
1 answer:
vivado [14]3 years ago
5 0

Problem 1

We're given that angle A = angle B. Also that angle B = angle C.

By the transitive property, we can say angle A = angle C.

So basically all three angles are equal to one another. Let's call that unknown angle x.

For any triangle, the three angles always add to 180, so,

x+x+x = 180

3x = 180

x = 180/3

x = 60

That proves angles A,B, and C are each 60 degrees. This triangle is considered equiangular since all angles are the same. Furthermore, the triangle is also considered equilateral meaning all sides are the same. The term equilateral is more widely used, so I'd go with that term if you could only pick one.

==========================================================

Problem 2

As mentioned in problem 1, the three angles of a triangle add to 180

A+B+C = 180

A+B+90 = 180

A+B+90-90 = 180-90

A+B = 90

This shows A and B are complementary angles. Complementary angles by definition add to 90 degrees.

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The volume of a cone is 16 pi cubic inches. Its height is 12 inches. What is the radius of the cone? 2 in. 4 in. 12 in. 16 in.
mart [117]

The radius of cone is 2 inches

<em><u>Solution:</u></em>

<em><u>The volume of cone is given by formula:</u></em>

V = \frac{\pi r^2h}{3}

Where,

"V" is the volume of cone

"r" and "h" are the radius and height of cone respectively

Given that, volume of a cone is 16 pi cubic inches

Its height is 12 inches

Therefore, we get,

V = 16 \pi cubic inches

h = 12 inches

r = ?

<em><u>Substituting the values in formula, we get</u></em>

16 \pi = \frac{ \pi \times r^2 \times 12}{3}\\\\16 = 4r^2\\\\r^2 = 4\\\\r = \pm 2

Since, radius cannot be negative, ignore r = -2

Thus radius of cone is 2 inches

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3 years ago
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Which of the following equations represents a line that is parallel to the line that passes through the points below?
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Answer:

See below

Step-by-step explanation:

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Liono4ka [1.6K]

Answer:

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Step-by-step explanation:

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