Question

1. f(x) = 3x^3 - x^2 - 2x what are the possible rational zeros for this?

Answer 1

Answer:

here is the answer.....hope it helps you!❤️

Answer 2

Answer:

x = 0, $\frac{2}{3}$, and 1

Step-by-step explanation:

We have our equation 3$x^{3}$ - $x^{2}$ - 2x.

We can factor out an x like this:  x(3$x^{2}$ - x - 2)

From here, it is easy to see that: x(3x + 2)(x - 1)

Now, we just set our equation to 0 like this: 0 = x(3x + 2)(x - 1)

So,

• x = 0

• 3x - 2 = 0 ⇒ 3x = 2 ⇒ x = $\frac{2}{3}$

• x - 1 = 0 ⇒ x = 1