Answer:
The final answers are x = 1 OR x = -3.
Step-by-step explanation:
Given the equation is x^2 -3 = -2x
Rewriting it in quadratic form as:- x^2 +2x -3 = 0.
a = 1, b = 2, c = -3.
Using Quadratic formula as follows:- x = ( -b ± √(b² -4ac) ) / (2a)
x = ( -2 ± √(4 -4*1*-3) ) / (2*1)
x = ( -2 ± √(4 +12) ) / (2)
x = ( -2 ± √(16) ) / (2)
x = ( -2 ± 4 ) / (2)
x = (-2+4) / (2) OR x = (-2-4) / (2)
x = 2/2 OR x = -6/2
x = 1 OR x = -3
Hence, final answers are x = 1 OR x = -3.
Answer:
No, Ivory is incorrect. The equation does have a solution, and the solution is x = -1.
Step-by-step explanation:
We try to solve the equation first.
2x + 2 = x + 1
We want all variables on the left side and all numbers on the right side.
Subtract x from both sides.
x + 2 = 1
Subtract 2 from both sides.
x = -1
Check: Plug in -1 for x on both sides and see if it makes a true statement.
2x + 2 = x + 1
2(-1) + 2 = -1 + 1
-2 + 2 = 0
0 = 0
0 = 0 is a true statement, so the solution x = -1 is the correct solution.
Answer: Ivory is incorrect. The equation does have a solution, and the solution is x = -1.
4 radical 1250^3.
The 3 stays on the inside, hope this helps.
Answer:
fyi b's answer has imaginary numbers in it...
Imaginary: 1 +
Imaginary: 1 -
Step-by-step explanation:
= 
... the negative root will produce imaginary solutions
