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Paha777 [63]
3 years ago
11

What environmental hazards exist because of man’s desire for profit?

Computers and Technology
2 answers:
Anastasy [175]3 years ago
5 0
Cutting down trees for paper
LiRa [457]3 years ago
4 0
Global warming because of need for fossil fuels.
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Mice21 [21]
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LAB: Count characters - methods
tangare [24]

Answer:

i hope understand you

mark me brainlist

Explanation:

using namespace std;

#include <iostream>

 

#include <string.h>

#include <stdlib.h>

#include <stdio.h>

 

#define BLANK_CHAR (' ')

 

 

int CountCharacters(char userChar, char * userString)

{

 

int countReturn=0;

 

int n = strlen(userString);

 

for (int iLoop=0; iLoop<n; iLoop++)

{

       if (userString[iLoop]==userChar)

       {

        countReturn++;

 }

}

return(countReturn);

}

 

/******************************************

    Removes white spaces from passed string; returns pointer

     to the string that is stripped of the whitespace chars;

   

  Returns NULL pointer is empty string is passed;  

     Side Effects:

 CALLER MUST FREE THE OUTPUT BUFFER that is returned

 

 **********************************************************/

char * RemoveSpaces(char * userString)

{

 

 char * outbuff = NULL;

 

 if (userString!=NULL)

 {

   int n = strlen(userString);

    outbuff = (char *) malloc(n);

 

   if (outbuff != NULL)

   {

          memset(outbuff,0,n);

          int iIndex=0;

          //copies non-blank chars to outbuff

         for (int iLoop=0; iLoop<n; iLoop++)

         {

           if (userString[iLoop]!=BLANK_CHAR)

          {

           outbuff[iIndex]=userString[iLoop];

           iIndex++;

   }

   

   } //for

         

   }

   

   }

 return(outbuff);

 

}

 

 

int main()

{

 

 char inbuff[255];

 cout << " PLEASE INPUT THE STRING OF WHICH YOU WOULD LIKE TO STRIP WHITESPACE CHARS :>";

 gets(inbuff);

 

 char * outbuff = RemoveSpaces(inbuff);

 if (outbuff !=NULL)

 {

    cout << ">" << outbuff << "<" << endl;

    free(outbuff);

    }

     

   memset(inbuff,0,255);  

   cout << " PLEASE INPUT THE STRING IN WHICH YOU WOULD LIKE TO SEARCH CHAR :>";

gets(inbuff);

 

  char chChar;

 cout << "PLEASE INPUT THE CHARCTER YOU SEEK :>";

 cin >> chChar;

 

 int iCount = CountCharacters(chChar,inbuff);

 cout << " char " << chChar << " appears " << iCount << " time(s) in >" << inbuff << "<" << endl;

 

}

4 0
3 years ago
What is a good practice to remember when adding transitions to a presentation?
storchak [24]

Answer:

A. Use one type of transition throughout.

Explanation:

Edge 2021.

7 0
3 years ago
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Create a new Java program called MyInfo. Create one or more method(s) that pass the following information as parameters and prin
Vladimir79 [104]

Answer:

Answered below

Explanation:

//Program in Java

class MyInfo{

public static void main (String args []){

myFullName("John", "Doe");

myAgeMajorGPA(20, "Biology", 4.3);

}

public void myFullName(String initialName, String middleName){

System.out.println(initialName);

System.out.print(middleName);

}

public void myAgeMajorGPA(int age, String major, double GPA){

System.out.println(age);

System.out.println(GPA);

System.out.print(major);

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3 0
3 years ago
In this exercise we will practice using loops to handle collections/containers. Your job is to write a program that asks the use
kati45 [8]

Answer:

In Python:

chars = 'abcdefghijklmnopqrstuvwxyz'

letter = input("Sentence: ")

for i in range(len(chars)):

   count = 0

   for j in range(len(letter)):

       if chars[i] == letter[j].lower():

           count = count + 1

   if count > 0 :

       print(chars[i]+": "+str(count)+" times")

Explanation:

This initializes the characters of alphabet from a-z

chars = 'abcdefghijklmnopqrstuvwxyz'

This prompts the user for sentence

letter = input("Sentence: ")

This iterates through the initialized characters

for i in range(len(chars)):

This initializes count to 0

   count = 0

This iterates through the input sentence

   for j in range(len(letter)):

This compares the characters of the sentence with alphabet a-z

       if chars[i] == letter[j].lower():

If there is a match, count is incremented by 1

           count = count + 1

If there is an occurrence of character,

   if count > 0 :

The character and its count is printed

       print(chars[i]+": "+str(count)+" times")

5 0
3 years ago
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