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2 years ago

NO RUSH i just cannot figure this out

Mathematics

2 answers:

yuradex [85]2 years ago

7 0

The answer is Michele letter C

Tomtit [17]2 years ago

6 0

Hi There! I am Not the best at Math But I hope this helps.

<h3>Lets firstly Cross some people out. Michelle, It's not very Likely for them to be able to Succeed that amount but even so, they'd have to Go through all of them to make sure if A singular one was correct.</h3><h3>Liam Is next to go, As Michelle, His has far too many trials. He'd have to go through each and everyone of them To find the correct one.</h3><h3>It's more or so now stuck between Isaac and Latoya</h3><h3 />

I hope this somewhat Helped you! Good Luck!

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Please help me with this

expeople1 [14]

Answer:

4 3/4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is -9+n/4=-7? Please explain in detail, I don’t really understand this at all.

Brrunno [24]

Answer:

n=-19

Step-by-step explanation:

-9+n/4=-7

Multiply 4 on both sides

-9+n=-28

Add 9 on both sides

n=-19

5 0

3 years ago

If 64 seedlings are allowed 24cm? of space ?<br> How much space should be allowed for 48 seedlings?

Monica [59]

128 cm square space is required for 48 seedlings

check

for 1 seedlings= 64÷ 24

= 2.66

for 48 seedlings = 2.66666667× 48 = 128

if right plz give Brainliest would really appreciate it.

Thank u

Be safe

Be healthy

3 0

3 years ago

Which notation is expressed in interval notation x> -2?

vfiekz [6]

Answer:

$( - 2 \: \infty )$

5 0

3 years ago

A professor records the difference between the marks scored by the students in the class test last week and those scored in the

dezoksy [38]

Answer: $(10.82\ , 13.18)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\mu\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n= 35 , large sample (n>30)

Mean difference : $\overline{x}=12$

Standard deviation : $\sigma=3$

Significance level : $\alpha=- 1-0.999=0.001$

Critical value : $z_{\alpha/2}=z_{0.0005}=3.4807567$

Now, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students will be :-

$12\pm\ (3.4807567)\dfrac{2}{\sqrt{35}}\\\\=12\pm1.18\\\\=(10.82\ , 13.18)$

Hence, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students = $(10.82\ , 13.18)$

4 0

3 years ago