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2 years ago

Y is directly proportional to x and k is a constant. Which equation

Mathematics

2 answers:

inn [45]2 years ago

7 0

It would be Y=kx.
Look at photo for explanation

Andre45 [30]2 years ago

5 0

Answer:

y = kx

Step-by-step explantion:

We did this in math class and I know it is right! I hope this helps you! :)

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What is the real part of the complex number when 4 plus 5i is multiplied with 2 minus i?

Nady [450]

Answer:

What I do not understand what you are asking, can you repeat it pls.

Step-by-step explanation:

3 0

3 years ago

Show that cos(3x) = cos3(x) − 3 sin2(x)cos(x). (Hint: Use cos(2x) = cos2(x) − sin2(x) and the cosine sum

otez555 [7]

<u>Step-by-step explanation:</u>

To prove:

$\cos 3x=\cos^3x-3\sin^2 x\cos x$

Identities used:

$\cos(A+B)=\cos A\cos B+\sin A\sin B$ ......(1)

$\sin 2A=2\sin A\cos A$ ........(2)

$\cos 2A=\cos^2A-\sin^2 A$ .......(3)

Taking the LHS:

$\Rightarrow \cos 3x=\cos (x+2x)$

Using identity 1:

$\Rightarrow \cos (x+2x)=\cos x\cos 2x-\sin x\sin 2x$

Using identities 2 and 3:

$\Rightarrow \cos x(\cos ^2x-\sin^2 x)-\sin x(2\sin x\cos x)\\\\\Rightarrow \cos^3x-\sin^2x\cos x-2\sin^2 x\cos x\\\\\Rightarrow \cos^3x-3\sin^2x\cos x$

As, LHS = RHS

Hence proved

4 0

2 years ago

A tabletop in the shape of a trapezoid has an area of 5,658 square centimeters. Its longer base measures 119 centimeters, and th

Sedaia [141]

The formula for finding the area of a trapezoid is: sum of bases*height*1/2
By plugging in the information that we already have, we know: (119+65)*height*1/2=5658
184*1/2*height=5658
92*height=5658
height=61.5cm.

Check:
119+65=184
184*61.5=11316
11316*1/2=5658

3 0

3 years ago

find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}

inn [45]

Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2 and x" = [10 - √64]/2

x' = (10+12)/2 and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity

6 0

3 years ago

Jaclyn estimates that the square root of 50 in the following way: √50 = 2√25 = 2*5 = 10

Harman [31]

Answer:

Jacklyn is wrong because

$\sqrt{50} \ne2 \sqrt{25 }$