Answer:
hmax = 628 ft
Step-by-step explanation:
The bullet will reach its maximum height when its velocity h'(t) becomes zero. The equation of motion is
h(t) = -16t^2 + 200t + 3
Taking the derivative of h(t) is
h'(t) = -32t + 200
Solving for t when h'(t) = 0, we get
t = 200/32 = 6.25 s
and this is the time it takes for the bullet to reach its maximum height. Using this value for t into h(t), we get
h = -16(6.25 s)^2 + 200(6.25 s) + 3
= 628 ft
Answer:
Step-by-step explanation:
hello : look this solution
25 + 60 = $85. 85/200 and x/100. 100 times 85= 8500. Divide 8500 by 200= 42.5 Hope this helps!
