The error bars are used to indicate the variability of the data presented in a graph.
There are several quantities that can be used to generate error bars in the graph. These are:
standard deviation
standard error
confidence interval
Usually, one standard deviation above and below the mean is used although it is advised to indicate which variability data is used to generate the error bars in the graph since the 3 quantity given are not equal.
Answer:
Step-by-step explanation:
![24 = \frac{x}{\frac{3}{8}} \\ \\ [24][\frac{3}{8}] = \frac{72}{8} = 9 \\ \\ 9 = x](https://tex.z-dn.net/?f=24%20%3D%20%5Cfrac%7Bx%7D%7B%5Cfrac%7B3%7D%7B8%7D%7D%20%5C%5C%20%5C%5C%20%5B24%5D%5B%5Cfrac%7B3%7D%7B8%7D%5D%20%3D%20%5Cfrac%7B72%7D%7B8%7D%20%3D%209%20%5C%5C%20%5C%5C%209%20%3D%20x)
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Answer:
<em>630 cups</em>
Step-by-step explanation:
<u>Percentages</u>
This problem is most easily solved backward, i.e., from the final data up to the beginning.
There was a new box of cups and the worker at a snack stand opened it. He first used 30 cups from the box and the second day he uses 15% of the remaining cups in the box, and we are told that represents 90 cups.
If 15% (0.15) equals 90 cups, then the number of cups before the second day was 90/0.15 = 600 cups.
On the first day, we used 30 cups, thus the original number of cups in the box was 600+30=630 cups
Answer:
Step-by-step explanation:
In Δ AFB,
∠AFB + ∠ABF + ∠A = 180 {Angle sum property of triangle}
90 + 48 + ∠1 = 180
138 + ∠1 = 180
∠1 = 180 - 138
∠1 = 42°
FC // ED and FD is transversal
So, ∠CFD ≅∠EDF {Alternate interior angles are congruent}
∠2 = 39°
In ΔFCD,
∠2 + ∠3 + ∠FCD = 180
39 + ∠3 + 90 = 180
129 +∠3 = 180
∠3 = 180- 129
∠3 = 51°
I think the answer will be 17 square that what my friend said.
