Answer:
He saw <u>1 duck</u> and <u>3 dogs</u>.
Step-by-step explanation:
Given:
Evan went to the park and saw four animals.
Each animal was either a duck or a dog.
He saw a total of 14 legs.
Now, to find the number of each animal he had seen.
Let the number of duck be 
And the number of dog be 
So, total number of animals:
Now, the total number of legs he did see:
<em>As we know the legs of a duck are 2 and a dog are 4.</em>
Adding both sides by -16 we get:
Dividing both sides by -2 we get:
The number of duck = 1.
Now, putting the value of 
in above equation we get:
The number of dogs = 3.
Therefore, he saw 1 duck and 3 dogs.
The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
<span>Assuming that this is referring to the same list of options that was posted before with this question, the correct response was the first one, although I forget what it was. </span>
Answer:
x = -11/5 and y = 24/5
Step-by-step explanation:
Use elimination.
First, we need to multiply so that at least one variable can cancel out.
We can multiply the top equation by 2.
So we get
4x + 6y = 20
Then, we can use elimination.
The x's cancel out.
So we get 5y = 24
Or y = 24/5
Then, we can plug in this y value back into the first equation to find x.
2x + 3(24/5) = 10
2x + 72/5 = 50/5
2x = -22/5
x = -11/5
So x = -11/5 and y = 24/5
Y = ax + b;
0.89 = a * 2 + b and 2.09 = a * 5 + b =>
=> 2.09 - 0.89 = a * 5 + a * 2 + b - b => 1.20 = 3 * a => a = 1.20 / 3 => a = 0.40;
b = 0.89 - 0.40 * 2 => b = 0.89 - 0.80 => b = 0.09;
y = 0.40x + 0.09 => 0.40x - y + 0.09 = 0 is the linear equation.
