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Irina18 [472]
3 years ago
9

11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

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T=\frac{1}{f}

multiply \space\ both \space\ sides \space\ by \space\ f

Tf=1

divide \space\ both \space\ sides \space\ by \space\ T

f=\frac{1}{T}
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Step-by-step explanation:

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If you know the y-intercept of a line what else do you need to write it equal
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Step-by-step explanation:


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Determine the slope <br><br> 2y-4x=1
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Answer:

2

Step-by-step explanation:

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The equation is not simplified yet.

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3 years ago
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Answer: Choice A) 4/5

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Work Shown:

cos^2(theta) + sin^2(theta) = 1
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