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Irina18 [472]
3 years ago
9

11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

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See below.

Step-by-step explanation:

I'll show you step by step how to do the synthetic division.

You are dividing polynomial -6x^4 + 22x^3 + 3x^2 + 15x + 20 by x - 4.

From the polynomial, you only need the coefficients in descending order of degree as they are written.

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This is what the setup looks like. You can see it in the problem you were given.

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Multiply 4 by -5 and write it above and to the right. Add vertically.

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Multiply 4 by -5 and write it above and to the right. Add vertically.

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The 4 numbers in the second line are the coefficients of the quotient.

The quotient is 1 degree less than the original polynomial.

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The cost price of the table is $40.

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Let the cost of the table is $ x

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It is known that

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To know more about Gain

brainly.com/question/23385214

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