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olga55 [171]
3 years ago
13

A dilation maps point Q(1, 2) to its image Q’(2, 4). The completed figure Q’R’S’T’ is on the graph. What is the scale factor? En

ter your answer in the box.
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

2 is the scale factor

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What is 2 to the power of four thirds equal to?
Yanka [14]

Answer:

This is the cube root of 16

Step-by-step explanation:

2 ^ (4/3)

2^4 = 16

16 ^(1/3)

This is the cube root of 16

5 0
3 years ago
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Question 6 (1 point)
Alika [10]
59 cans ... she counting up by 5s so multiply 5 x 10
6 0
3 years ago
I need help!!
Natasha2012 [34]

Answer:

The exact solution is

x = \frac{Ln(60)}{7*Ln(5)}

And the approximation to three decimal places is:

x = 0.363

Step-by-step explanation:

Here we have the equation:

5^{7*x} = 60\\

Now we can remember a property of the natural logarithm function:

Ln(a^n) = n*Ln(a)

Now we can apply the Ln( ) function to both sides of that equation to get:

Ln(5^{7*x}) = Ln(60)

Then we get:

7*x*Ln(5) = Ln(60)

Solving that for x we get:

x = \frac{Ln(60)}{7*Ln(5)}  = 0.363

So the exact solution is:

x = \frac{Ln(60)}{7*Ln(5)}

And the approximation to three decimal places is:

x = 0.363

7 0
3 years ago
Stuffed animals each weighing 1/4 pound are on a scale. The scale shows 1 1/2 pounds. How many stuffed animals are on the scale?
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7 0
2 years ago
Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s
-BARSIC- [3]

Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on  a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0
3 years ago
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