<u>Answer:
</u>
Two required integers are 5 and 10.
<u>
Solution:
</u>
Given that a positive integer is twice another. The sum of the reciprocals of the positive integers is
We have to find the two integers.
Let assume that one integer = x
Since another integer is twice of first one, so second integer = 2x
Reciprocal of first integer =
Reciprocal of first integer =
Given that sum of reciprocal =
On solving above equation for x,
2x=10
x=5
First integer = x = 5
Second integer = 2x = 10
Hence two required integers are 5 and 10.
Answer:
The solution is:
Part A. which is sqrt(5)^7k/3[/tex]
Part B. k = 18/7
Step-by-step explanation:
Part A.
To solve this part, we're going two use THREE important properties of exponents:
1.
2.
3.
Let's work the numerator using the properties 1, 2 and 3:
Let's work the denominator using the properties 1, 2 and 3:
Now dividing the numerator by the denominator:
Part B
if
Then:
So
Solving for k, we have:
k = 18/7
Answer:
342
Step-by-step explanation:
you take the fifteen and devide it by its whole munber of the problem
Answer:
12 and - 12 is the correct answer
- 3 x = 36
x = -12
again
3x = 36
x = 12