Answer:
A) 
Step-by-step explanation:


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** From what the problem said, we know that we selected the correct equation.
I am joyous to assist you anytime.
Volume of pyramid:

A - base area
H - height
First count volume of one pyramid:
![V=\dfrac{1}{3} \cdot 3 \cdot 4=4 [\hbox{inch}^3]](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Ccdot%203%20%5Ccdot%204%3D4%20%5B%5Chbox%7Binch%7D%5E3%5D)
So by using 576 inch^3 you can make 576 : 4 =
144 pyramids
The quadrants are as follows:
The 1st quadrant has the points which have both x and y positive and the 3rd quadrant has the points which have both x and y negative. If the ordered pair and the same x and y value, if ons is positive, the other also is, and the same for negative.
So, at first we see that there are point where the x and y are the same and that are in the 1st or 3rd quadrant.
However, there is one special case:
When x and y are 0, that is, the ordered pair is (0, 0).
Since this point is the origin, it doesn't lie on any of the quadrants.
Thus, this affirmative is sometimes true. Every point but (0, 0) that have same x and y values are in the 1st or 3rd quadrant except for (0, 0).
Answer:
Step-by-step explanation:
You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.
Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.
Total of scale usage is 2
b) if you have
coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.
Step 1: you narrow down to group of
coins
Step 2: you narrow down to group of
coins
Step 3: you narrow down to group of
coins
...
Step n: Step 1: you narrow down to group of
coin