The equation would be y = -2/3x + 8
The equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)^2 + (y-(-4))^2 = r^2
(x-5)^2 + (y+4)^2 = r^2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))^2+((-4)-2)^2]^1/2
r = [8^2 + (-6)^2]^1/2
r = [64 + 36]^1/2
r = 100^1/2
r= 10
The final equation is:
(x-5)^2 + (y+4)^2 = 10^2
Answer:
The answer is
<h2>( 3 , - 1)</h2>
Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(2, -3) and (4, 1)
The midpoint is
We have the final answer as
<h3>( 3 , - 1)</h3>
Hope this helps you
The result of an absolute value operation is never negative. So the smallest that the expression |x+5| can be is 0.
Tacking on "-8" to |x+5| leads to |x+5|-8
The range of this is [-8, infinity) since the smallest |x+5|-8 can be is -8. All I did was subtract 8 from the smallest value of |x+5|
Final Answer: choice C)
Answer:
x=x
Step-by-step explanation:
3x - 2 = 3 (x - 2/3)
3x - 2 = 3x - 6/3
3x - 2 = 3x - 2
- 2 - 2
3x = 3x
/3 /3
x = x
