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Alexeev081 [22]
2 years ago
7

CAN SOMEONE PLEASE CHECK MY ANSWER!!

Mathematics
1 answer:
Stells [14]2 years ago
4 0

Answer:

Yesss, that's correct!

Step-by-step explanation:

Good luck!!!!

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If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

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Find the value of x and y that will make each quadrilateral a parallelogram.​
Tatiana [17]

Answer:

the opposite Angles sum up to give 180

Step-by-step explanation:

3y +3y = 180

y=30

if y = 30 the x = 55

are you clear?

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Help this is due today.
Vika [28.1K]
Dominic would be the answer because the exponents add together
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When graphed, the circle with equation x2 + y2 - 10x + 16 = 0 will lie ENTIRELY in Quadrants...
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