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Inessa [10]
3 years ago
9

Hello! :) please give an explanation for what is wrong and what should be done to fix this issue.

?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B64%7D%20%7D%7B%5Csqrt%7B64%7D%20%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B64%7D%7B64%7D%20%7D%20%3D1" id="TexFormula1" title="\frac{\sqrt[3]{64} }{\sqrt{64} } = \sqrt[3]{\frac{64}{64} } =1" alt="\frac{\sqrt[3]{64} }{\sqrt{64} } = \sqrt[3]{\frac{64}{64} } =1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

<h2>½</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • redical
<h3>tips and formulas:</h3>
  • \sqrt[n]{ \frac{y}{x} }  <  =  >  \frac{ \sqrt[n]{y} }{ \sqrt[n]{x} }
<h3>let's solve:</h3>
  • it's wrong because it doesn't follow the redical formula. it took one cube root and another square root which is wrong. both should be cube root According to the formula

let's fix the issue

  • since there are a cube root and square root therefore we can't use the formula
  1. \sf simplify \: roots :  \\  \tt   = \frac{  \sqrt[3]{64}  }{ \sqrt{64} }  \\   = \frac{4}{8}  \\  =  \frac{1}{2}
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