All categories

3 years ago

I need help on question b please it hard

Mathematics

1 answer:

Dimas [21]3 years ago

4 0

Answer:

For each line you have to have 3 numbers that would add up to 2 km.

Step-by-step explanation:

For example:

The first line has 1600m and you need to figure out what the other two are. Each line has to add up to 2 km.

<em>Hope this helps :)</em>

You might be interested in

Can someone explain how to do this please?

Rufina [12.5K]

for the columns where is less than or equal zero, use the first line of the function to calculate the value of f(x)

${ ( \frac{1}{3} ) }^{ - 2} - 1 = 9 - 1 = 8 \\ { ( \frac{1}{3} ) }^{ - 1} - 1 = 3 - 1 = 2 \\ { ( \frac{1}{3} ) }^{ 0} - 1 = 1 - 1 = 0$

for every x greater than zero, use the second line to determine the value

${3}^{1} - 2 = 3 - 2 = 1 \\ {3}^{2} - 2 = 9 - 2 = 7$

hope this helps and gives some insight what to do.

if there are open questions left, feel free to ask them in the comments

have a beautiful day

-Alex

3 0

3 years ago

If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?

Ludmilka [50]

Answer:

Step-by-step explanation:

y = k*x This is the formula for a direct variation.

y = 20
x = 4 Substitute these values into the direct variation

20 = 4 * k Divide by 4

20/4 = 4k/4

k = 5

Answer: the constant of variation is 5

7 0

3 years ago

A bag contains 48 balls

FrozenT [24]

Answer:

25 Balls

Step-by-step explanation:

6 0

3 years ago

During a football game, a team lost 12 yards on the first play and then gained 5 yards on each of the next 3 plays. Which method

agasfer [191]

-12 + 5(3) = total yards at the end

So your answer would be 3 yards

6 0

3 years ago

Read 2 more answers

Serena has $130 in her bank account . Her account is compounded quarterly for 2 years at a 9.4% interest rate . What is her tota

____ [38]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$130\\
r=rate\to 9.4\%\to \frac{9.4}{100}\to &0.094\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &2
\end{cases}
\\\\\\
A=130\left(1+\frac{0.094}{4}\right)^{4\cdot 2}\implies A=130(1.0235)^8$

7 0

3 years ago