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alexandr1967 [171]
3 years ago
10

Can someone help me please!!! Thank you

Mathematics
1 answer:
Semmy [17]3 years ago
5 0

Steps of construction:

1. Draw a circle with centre B.

2. Draw a circle with centre C.

3. Both circles intersect each other at a point D

4. Join A and D.

5. So, AD bisects angle CAB.

<em>A </em><em>rough </em><em>figure </em><em>is </em><em>shown</em><em> </em><em>in </em><em>the </em><em>picture</em><em>.</em>

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If a, b, 72, (a+b) are consecutive terms of an A.P., find the values of a and b.​
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Answer:

a = 36, b = 54

Step-by-step explanation:

Since the terms are in arithmetic progression then there is a common difference d between consecutive terms , that is

b - a = 72 - b ( add b to both sides )

2b - a = 72 → (1)

and

a + b - 72 = b - a ( subtract b - a from both sides )

2a - 72 = 0 ( add 72 to both sides )

2a = 72 ( divide both sides by 2 )

a = 36

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Substitute a = 36 into (1) and evaluate for b

2b - 36 = 72 ( add 36 to both sides )

2b = 108 ( divide both sides by 2 )

b = 54

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Thus a = 36 and b = 54

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3 years ago
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Answer:

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