Answer:
a) distance covered by hare d1 = 8t
b) distance covered by tortoise d2 = 5t + 550
c) ∆d = 550 - 3t
Step-by-step explanation:
Given;
Speed of hare u = 8m/s
Speed of tortoise v = 5 m/s
Initial distance of tortoise d0 = 550 m
a) using the equation of motion;
distance covered = speed × time + initial distance
d = vt + d0
For hare;
d0 = 0
Substituting the values;
d1 = 8t + 0
d1 = 8t
b)using the equation of motion;
distance covered = speed × time + initial distance
d2 = vt + d0
For tortoise;
d0 = 550m
Substituting the values;
d2 = 5t + 550
d2 = 5t + 550 m
c) the number of meters the tortoise is ahead of the hare.
∆d = distance covered by tortoise - distance covered by hare
∆d = d2 - d1
Substituting the values;
∆d = (5t + 550) - 8t
∆d = 550 - 3t
Answer:
88%
Step-by-step explanation:
Answer:
just type the values in your google
Step-by-step explanation:
7,9,10 in that order in the y portion on the chart are the answers then use the x and y answers as graphing points for example the first one your going to graph is (3,7)
Answer:
The slope of the given line and a line parallel to it is 5/2.
Step-by-step explanation:
Explanation:
Given:
5
x
−
2
y
=
11
is the standard form of a linear equation.
A line parallel to this line has the same slope. To determine the slope, solve for
y
to change the equation to slope-intercept form:
y=mx+b, where: m is the slope and b is they intercept.5x−2y=11
Subtract 5x from both sides. −2y=−5x+11
Divide both sides by −2. y=−5/−2x+11/2
Simplify. y=5/2 x −11/2
The slope of the given line and a line parallel to it is 5/2.
.