Perpendicular lines have gradients that multiply to give -1
So, the gradient of the line we need is -1/0.2 = -5
If we have the gradient and a point in the line, we can work out the equation using the formula:
y - y1 = m(x - x1)
where m = gradient, y1 = y-coordinate and x1 = x-coordinate of the same point
So, we substitute in our values, and we get:
y - -8 = -5(x - -7)
y+8 = -5x-35
y = -5x-43
Hope I helped! xx
Answer:
2050
Step-by-step explanation:
Answer:
C.g(x) = 5x²
Step-by-step explanation:
To find the equation for the function g(x), use the format for a quadratic equation. Without any up/down and left/right shifts, the form is y = ax².
Substituting "x" and "y" into the equation tells you if a point is on the graph.
"a" tells you the vertical stretch (greater than 1) or compression (greater than 0, less than 1).
In f(x) = x², a = 1 even though it's not written.
<u>Use the point (1, 5) on g(x) and substitute it</u> into the form for a quadratic function. Remember points are (x, y), so x = 1 and y = 5.
g(x) = ax²
y = ax² In function notation, g(x) replaces the "y". Switch it back to "y".
5 = a(1)² Substitute x = 1 and y = 5
5 = a(1) Solve the exponent first. (1)² = 1
5 = a When you multiply "a" by 1, the answer is just "a".
a = 5 Solved for "a". Put variable on left side for standard formatting.
With the quadratic form, substitute "a" into g(x).
y = ax²
g(x) = 5x²
The answer is:
f(x)=3x^2 - 2x + 5
Hope this helped :)
