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Tasya [4]
2 years ago
13

The cost of C (in dollars) of making n watches is represented by C=15n+85. How many watches are made when the cost is $385?

Mathematics
1 answer:
hichkok12 [17]2 years ago
4 0

well...

15 x 20 = 300

300+85 = 385


you can get 20 watches for $385


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Step-by-step explanation:

(0,5) and (-2,-3)

y=mx+b

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Substitute (0,5) or (-2,-3)

For easy processing substitute : (0,5)

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3 years ago
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Answer:

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Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

P(\text{Lemon-lime})=\frac{1}{3}

Let us find probability of finding one orange drink.

P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

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Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

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