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Tasya [4]
2 years ago
13

The cost of C (in dollars) of making n watches is represented by C=15n+85. How many watches are made when the cost is $385?

Mathematics
1 answer:
hichkok12 [17]2 years ago
4 0

well...

15 x 20 = 300

300+85 = 385


you can get 20 watches for $385


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8x-3(2x-4)≤ 3(x-6)
OlgaM077 [116]

The solution to the inequality expression is x ≥ 30

<h3>How to solve the inequality expression?</h3>

The inequality expression is given as:

8x - 3(2x - 4) ≤ 3(x - 6)

Open the brackets in the above inequality expression

8x - 6x + 12 ≤ 3x - 18

Collect the like terms in the above inequality expression

8x - 6x - 3x  ≤ -12 - 18

Evaluate the like terms in the above inequality expression

-x  ≤ -30

Divide both sides of the above inequality expression by -1

x ≥ 30

Hence, the solution to the inequality expression is x ≥ 30

Read more about inequality expression at

brainly.com/question/24372553


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8 0
1 year ago
Someone please help 5 points.
choli [55]

Answer:

7.1 I am pretty sure okay cya

4 0
3 years ago
Read 2 more answers
Simplify the given expression below:
ira [324]
The answer is A. -2+5i.

First you set up the problem like this: (6+2i)-(8-3i)
Then you distribute the (-) into the second parenthesis. After doing that you should have something that looks like this: 6+2i-8+3i
Then you add like terms.
6 0
2 years ago
Read 2 more answers
4. Assume that you have a part-time job at which you work 20 hours per week at the rate
charle [14.2K]

Answer:

0.125

7.50/60=1.25

since there 60 minutes in one hour you would divide the hourly rate by 60.

8 0
3 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
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