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OverLord2011 [107]
4 years ago
9

how can opportunity and equality's bring society together (I'm interested in everyone's answers best ones brainlist)​​

Mathematics
1 answer:
Vilka [71]4 years ago
5 0
By getting to interact and be smart about the friends your making
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Follow the steps to simplify this expression.
PSYCHO15rus [73]

Answer:

3x - 9

Step-by-step explanation:

We already have the expression 4x + 2x − 3x − 9. Now, we just have to add like-terms. This will give us 3x - 9.

6 0
2 years ago
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Nate is selling a DVD of one performance for $19.99. This is the price after a discount of 25%. What was the original price of t
IrinaVladis [17]

Answer:

Exact: $79.96 Rounded: $80.00

Step-by-step explanation:

25% x 4 = 100%

thus $19.99 x 4 = $79.96. Rounded up to $80.00

5 0
3 years ago
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OKAY I'M RE-ASKING BECAUSE I STILL DON'T UNDERSTAND
maksim [4K]
The equation is y=5/6x

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3 years ago
Which quadrilateral is a parallelogram
Arada [10]
They are both quadrilatersand they are both parallelograms
 
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3 years ago
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A 10 ft ladder is being pulled away from a wall at a rate of 3 ft/sec. What is the rate of change in the area beneath the ladder
andriy [413]

Answer:

The rate of change in the area beneath the ladder is 5.25 ft²/s

Step-by-step explanation:

Area of triangle is given by;

A = \frac{1}{2}bh\\\\2A = bh\\\\take \ derivative  \ of \ both \ sides \ with \ respect  \ to \ "t"\\\\2\frac{dA}{dt} = h\frac{db}{dt} + b\frac{dh}{dt}\\\\divide \ through \ by \ 2\\\\\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}

where;

b is the base of the triangle, given as 6 ft

h is the height of the triangle, determined  by applying Pythagoras theorem.

h² = 10² - 6²

h² = 100 - 36

h² = 64

h = √64

h = 8 ft

Determine the rate of change of the height;

h^2 + b^2 = 10^2\\\\h^2 + b^2 =100\\\\2h\frac{dh}{dt} + 2b\frac{db}{dt} =0\\\\h\frac{dh}{dt} + b\frac{db}{dt} =0\\\\h \frac{dh}{dt}  = -b\frac{db}{dt} \\\\\frac{dh}{dt}  = (\frac{-b}{h} )\frac{db}{dt}\\\\\frac{dh}{dt}  =(\frac{-6}{8})(3)\\\\\frac{dh}{dt}  = -\frac{9}{4} \ ft/s

Finally, determine the rate of change of area beneath the ladder;

\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}\\\\\frac{dA}{dt} = (\frac{8}{2} )(3) + (\frac{6}{2}) (\frac{-9}{4})\\\\\frac{dA}{dt} = 12 - \frac{27}{4} \\\\\frac{dA}{dt} = \frac{48-27}{4}\\\\\frac{dA}{dt} = \frac{21}{4} \ ft^2/s\\\\\frac{dA}{dt} =  5.25 \ ft^2/s

Therefore, the rate of change in the area beneath the ladder is 5.25 ft²/s

5 0
3 years ago
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