All categories

3 years ago

Can someone please answer these for me?!

Mathematics

1 answer:

Advocard [28]3 years ago

7 0

Answer:

base : 9

three points : (1,0), (9,1), (81,2)

domain : x>0

range : all real number

asymptote : x=0

You might be interested in

Graph the image of the figure using the transformation given. Don't forget prime marks on your new image. Part 1: reflection acr

amm1812

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

J (1, 4 ) → J' (- 1, 4 )

K (1, 0 ) → K' (- 1, 0 )

L (4, 3 ) → L' (- 4, 3 )

Plot the points J', K', L' and connect them in order to obtain image

4 0

3 years ago

Whats the equation for this

yawa3891 [41]

Answer:

$x^2 + y^2 + 4x + 4y = -119/16$

Step-by-step explanation:

The axes x and y are calibrated in 0.25

If the circle is carefully considered, the radius r of the circle is:

r = -1.25 - (-2)

r = 0.75 units

The equation of a circle is given by:

$(x - a)^2 + (y - b)^2 = r^2$

The center of the circle (a, b) = (-2, -2)

Substituting (a, b) = (-2, -2) and r = 0.75 into the given equation:

$(x - (-2))^2 + (y - (-2))^2 = (3/4)^2\\\\(x + 2)^2 + (y + 2)^2 = (3/4)^2\\\\x^2 + 4x + 4 + y^2 + 4y + 4 = 9/16\\\\x^2 + y^2 + 4x + 4y + 8 = 9/16\\\\16x^2 + 16y^2 + 64x + 64y + 128 = 9\\\\16x^2 + 16y^2 + 64x + 64y = -119\\\\x^2 + y^2 + 4x + 4y = -119/16\\$

5 0

3 years ago

Amir has $50 to spend. She wants to buy a CD for $20 and spend the rest on jewelry sets which cost $8 each. Write an inequality

Aleksandr [31]

X = The amount of cd's
Y = Jewelry sets
X + Y = 50
X + 8y<_50
20 + 8Y<_50
Subtract 20 from both sides.
8Y<_30
Divide by 8 on both sides
Y<_3.75 (3 total)
She can buy 3 jewelry sets.

4 0

3 years ago

Daniel made 6 out of 15 free throw shots. about how many out of the next 10 free throw shots would you expect him to make?

insens350 [35]

C) 4

x/10 = 6/15

x = (6/15) (10)

x = 60/15 = 4

7 0

4 years ago

Read 2 more answers

A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial,

Tresset [83]

Answer:

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

$H = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]$

As we know that,

The matrix is a Markov chain $x_{k+1} = Hx_{k}$

Let

The initial state vector be

$x_{0} = \left[\begin{array}{ccc}1\\0\\0\end{array}\right]$

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

$x_{1} = Hx_{0} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}1\\0\\0\end{array}\right] \\= \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

∴ we get

$x_{1} = \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

Now,

$x_{2} = Hx_{1} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right] \\= \left[\begin{array}{ccc}0.25+0.0625+0.0625\\0.125+0.125+0.0625\\0.125+0.0625+0.125\end{array}\right]\\= \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]$

∴ we get

$x_{2} = \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]$

∴ we get

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

4 0

3 years ago