Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
![F(5) - F(-2) = 10](https://tex.z-dn.net/?f=F%285%29%20-%20F%28-2%29%20%3D%2010)
![\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}](https://tex.z-dn.net/?f=%5Cfrac%7BF%285%29-F%28-2%29%7D%7B5-%28-2%29%7D%20%3D%20%5Cfrac%7B10%7D%7B5-%28-2%29%7D)
![\bar f = \frac{10}{7}](https://tex.z-dn.net/?f=%5Cbar%20f%20%3D%20%5Cfrac%7B10%7D%7B7%7D)
The average value of
over the interval
is
.
Answer:
27, 12, and 36 = 108
22 and 4 = 44
14 and 12 = 84
25 and 8 =200
9, 8, and 7 = 504
32, 24, and 18 = 288
Step-by-step explanation: You are welcome.
Answer:
25
Step-by-step explanation:
![11\% \: of \: 230 \\ \\ = \frac{11}{100} \times 230 \\ \\ = 0.11 \times 230 \\ \\ = 25.3 \\ = 25](https://tex.z-dn.net/?f=11%5C%25%20%5C%3A%20of%20%5C%3A%20230%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B11%7D%7B100%7D%20%20%5Ctimes%20230%20%5C%5C%20%20%5C%5C%20%20%3D%200.11%20%5Ctimes%20230%20%5C%5C%20%20%5C%5C%20%20%3D%2025.3%20%5C%5C%20%20%20%3D%2025)
Hence 11% represents 25 students.
Answer:
m=-15
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable. m=-15
Answer:
The equation is:
![j/g=5/2](https://tex.z-dn.net/?f=j%2Fg%3D5%2F2)
Or, what is equivalent:
![j=5g/2](https://tex.z-dn.net/?f=j%3D5g%2F2)
Explanation:
This is the<em> table</em> that <em>shows the amount of lemon juice and sugar needed to make three different-sized batches of lemonade using the same recipe</em>:
Lemon juice (mL) Sugar (g)
Batch A 500 200
Batch B 750 300
Batch C 1500 600
You need to write an <em>equation to describe the relationship between j, the amount of lemon juice in mL and s, the amount of sugar in g</em>.
Calculate some ratios, to determine the kind of relation between the amount of juice and the amount of sugar in the recipe.
- Batch A: lemon juice / sugar = 500 / 200 = 5/2
- Batch B: lemon juice / sugar = 750/300 = 5/2
- Batch C: lemon juice / sugar = 1500/600 = 5/2
Hence, the amount of juice, j, and the amound of sugar, s, are proportional and the constant of proportionality is 5/2. From this, the equation is:
![j/g=5/2](https://tex.z-dn.net/?f=j%2Fg%3D5%2F2)
Or, what is equivalent (solving for j):
![j=5g/2](https://tex.z-dn.net/?f=j%3D5g%2F2)