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3 years ago

Identify the terms, coefficients, and constants in the expression. 8x+7y^2

Mathematics

1 answer:

alexandr1967 [171]3 years ago

5 0

Answer:

8x+7y^2

Step-by-step explanation:

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How do you find the value of 4!

prohojiy [21]

Answer:

Step-by-step explanation:

Factorial is applicable only for natural numbers and 0.

0! =1 trivially.

FOr other numbers, factorial is defined as 1x2x...n

For example 1! = 1

2! = 1x2 = 2

and so on.

i.e. n! = product of all natural numbers from 1 to n

= 1x2x....n

Using the above

we have n =4

Natural numbers from 1 to 4 are 1,2,3,4

Find the product of these 4 natural numbers to get 4!

4! = 1x2x3x4 = 24

3 0

3 years ago

Solve for each system of equations by substitution or elimination.

Tems11 [23]

QUESTION 1

The given system of equations are:

$y=x^2+5x+1$

$y=x^2+2x+1$

We equate the two equations to get:

$x^2+5x+1 =x^2+2x+1$

$x^2 - {x}^{2} + 5x - 2x = 1 - 1$

$3x = 0$

$x = 0$

When x=0,

$y=0^2+2(0)+1 = 1$

The solution is (0,1)

QUESTION 2

The given equations are:

$y=x^2-2x - 1$

and

$y= -x^2-2x-1$

We equate both equations to get:

$x^2-2x - 1 = -x^2-2x-1$

Group similar terms,

$x^2 + {x}^{2} -2x + 2x= -1 + 1$

$2 {x}^{2} = 0$

$x = 0$

We put x=0 into any of the equations to find y.

$y= -0^2-2(0)-1 = - 1$

The solution is (0,-1).

QUESTION 3

The given equations are:

$y=x^2+2x+1$

and

$y=x^2+2x-1$

We equate both equations:

$x^2+2x+1 = x^2+2x-1$

Group similar terms:

$x^2 -x^2+2x = -1 - 1$

$0 = -2$

This is not true.

Hence the system has no solution.

6 0

3 years ago

What logarithm is equal to 4log3?

gizmo_the_mogwai [7]

It would be log(81) because of the power rule...

5 0

2 years ago

Read 2 more answers

Solve the system of equations. \begin{aligned} & -5x+13y = -7 \\\\ & 5x+4y=24 \end{aligned} −5x+13y=−7 5x+4y=24 x= e

riadik2000 [5.3K]

Answer:

The solution of the given equations

x =4 , y = 1

Step-by-step explanation:

Explanation:-

Step(l):-

Given the system of equations -5x+13y = -7 ..(l)

5x+4y=24 ..(ll)

Step(ll)

Adding (l) and (ll) equations and cancelling '5x' terms we get

13y+4y = -7 +24

17y = 17

dividing '17' on both sides, we get

y=1

Step(lll):-

Substitute y=1 in equation (l) , we get

-5x+13y = -7

-5x + 13(1) = -7

subtracting '13' on both sides, we get

-5x +13 -13= -7 -13

-5x = -20

Dividing '-5' on both sides, we get

$x = \frac{-20}{-5}$

x = 4

Conclusion:-

The solution of the given equations

x =4 , y = 1

7 0

3 years ago

Please help me!!! some easy algebra

kow [346]

Answer:

5xy-x^2t+2x7+3x^2t= 7xy+2x^2t

Step-by-step explanation:

4 0

3 years ago

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