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3 years ago

Please Help! Look at attachments.

Mathematics

2 answers:

alekssr [168]3 years ago

8 0

Answer: As you can see Plumber A has a greater initial fee or greater y-intercept .so the answer is D.

Step-by-step explanation:

We know that plumber A has a initial fee of 100 but we need to find the initial fee and slope for plumber B.

(1,105) ( 2,160)

160 - 105 = 55

2-1 = 1

55/1 =5 so the slope for plumber B is 55

105 = 1(55) + b this is the formula used to find the y-intercept

105 = 55 + b

-55 -55

b= 50

So the equation for Plumber B is y = 55x + 50

Now compare equations y=55x + 50 and y= 30x + 100

marshall27 [118]3 years ago

4 0

Answer:

the answer is D.

Step-by-step explanation:

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Sholpan [36]

3 0

2 years ago

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

3 years ago

Quick algebra 1 question for 10 points!

Maslowich

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

<h3>What is the range of a quadratic equation?</h3>

In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.

x = - 9

y = (2 / 3) · (- 9)² - 6

y = 48

x = - 6

y = (2 / 3) · (- 6)² - 6

y = 18

x = - 3

y = (2 / 3) · (- 3)² - 6

y = 0

x = 0

y = (2 / 3) · 0² - 6

y = - 6

x = 3

y = (2 / 3) · 3² - 6

y = 0

x = 6

y = (2 / 3) · 6² - 6

y = 18

x = 9

y = (2 / 3) · 9² - 6

y = 48

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

To learn more on functions: brainly.com/question/12431044

#SPJ1

7 0

2 years ago

HELPPPPPP ITS URGENT!!!!!!!!!!!!!!!!!

PIT_PIT [208]

Answer:

Step-by-step explanation:

trust

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!! Justify each step in solving the equation (WILL GIVE BRAINLIEST!)

defon

2. Addition POE(property of equality)
3. Add variables
4. Subtraction of integers
5. Division of integer

4 0

3 years ago